The moving bullet of a gun has $10 \ g$ mass and $10^{-5} \ m$ uncertainty in position. Find the uncertainty in velocity.

(N/A) The uncertainty in the position is given by Heisenberg's Uncertainty Principle: $\Delta x \cdot \Delta v \ge \frac{h}{4 \pi \, m}$.
Rearranging for uncertainty in velocity: $\Delta v = \frac{h}{4 \pi \, m \, \Delta x}$.
Given: $h = 6.626 \times 10^{-34} \, J \, s$,$m = 10 \, g = 10^{-2} \, kg$,and $\Delta x = 10^{-5} \, m$.
Substituting the values: $\Delta v = \frac{6.626 \times 10^{-34}}{4 \times 3.1416 \times 10^{-2} \times 10^{-5}}$.
$\Delta v = \frac{6.626 \times 10^{-34}}{1.2566 \times 10^{-6}} = 5.27 \times 10^{-28} \, m \, s^{-1}$.